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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1
Let I(x)=∫(x+1)x(1+xex)2dx,x>0I(x)=\int \frac{(x+1)}{x\left(1+x e^{x}\right)^{2}} d x, x > 0. If lim⁡x→∞I(x)=0\lim \limits_{{x \rightarrow \infty}} I(x)=0, then I(1)I(1) is equal to
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Correct option: A
e+2e+1−log⁡e(e+1)\frac{e+2}{e+1}-\log _{e}(e+1)
Option B (x2+7x+12=0x^{2}+7 x+12=0) is correct because solving the given equation for z yields values for alpha and beta, whose sum and product are the roots of the equation x2+7x+12=0x^{2}+7 x+12=0.

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