JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

f:\left( { - 1,\;1} \right) \to B

, be a function defined by

f\left( x \right) = {\tan ^{ - 1}}\frac{{2x}}{{1 - {x^2}}}

, then

f

is both one-one and onto when

B

is the interval

View answer and explanation

Correct option: A

\left[ { - \frac{\pi }{2},\;\frac{\pi }{2}} \right]

Option B is correct because the range of the function is (-π/2, π/2) when f is both one-one and onto.

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