JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Easy

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Application +4 | -1

Consider a system of two identical particles in which first one is accelerating with

2 {~m} / {s}^2

and second one is at rest. The centre of mass of this system will have an acceleration

View answer and explanation

Correct option: B

1 {~m} / {s}^2

Option B (

1 {~m} / {s}^2

) is correct because the acceleration of the center of mass is the average of the individual accelerations.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)