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JEE MATHEMATICS MCQ: RELATIONS

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Let P={(x,y)∣x2+y2=1,x,y∈R}P=\left\{(x, y) \mid x^2+y^2=1, x, y \in R\right\}. Then PP is:
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Correct option: B
Symmetric
Option B (Symmetric) is correct because if (x,y)(x, y) is in PP, then x2+y2=1x^2 + y^2 = 1, which implies y2+x2=1y^2 + x^2 = 1, so (y,x)(y, x) is also in PP.

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