JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

If in a

\Delta \;ABC,\;2{b^2} = {a^2} + {c^2}

, then

\frac{{\sin 3B}}{{\sin B}}

is equal to

View answer and explanation

Correct option: D

{\left( {\frac{{{c^2} - {a^2}}}{{2ca}}} \right)^2}

Option D (

{\left( {\frac{{{c^2} - {a^2}}}{{2ca}}} \right)^2}

) is correct because it is the simplified form of

\frac{{\sin 3B}}{{\sin B}}

using the given condition and trigonometric identities.

More Questions from PROPERTIES OF TRIANGLES

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A

2 s