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JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Application +4 | -1
An electron and a photon each have a wavelength of 1.00 nm1.00 \mathrm{~nm}. Find

(a) their momenta,

(b) the energy of the photon, and

(c) the kinetic energy of electron. (Take h=6.63×10−34 Jsh=6.63 \times 10^{-34} \mathrm{~Js})
View answer and explanation
Correct option: A
6.63×10−25 kg ms−1;1.24 keV;1.51 eV6.63 \times 10^{-25} \mathrm{~kg} \mathrm{~ms}^{-1}; 1.24 \mathrm{~keV}; 1.51 \mathrm{~eV}
Option A (6.63×10−25 kg ms−1;1.24 keV;1.51 eV6.63 \times 10^{-25} \mathrm{~kg} \mathrm{~ms}^{-1}; 1.24 \mathrm{~keV}; 1.51 \mathrm{~eV}) is correct because it correctly calculates the momentum, photon energy, and electron kinetic energy using the given wavelength.

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