JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Analyzing +4 | -1

Let

P

be the point (other than the origin) of intersection of the curves

{y^2} = 4ax

and

a{y^2} = 4{x^3}

such that the normals to the two curves meet

x

-axis at

{G_1}\,and\,{G_2}

respectively. Then,

{G_1}{G_2} =

View answer and explanation

Correct option: B

4a

Option B (

4a

) is correct because it is the distance between the x-intercepts of the normals to the two curves at their point of intersection.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z