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JEE PHYSICS MCQ: OSCILLATIONS

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A pendulum is oscillating at a frequency of 8 Hz. Suddenly the string of the pendulum is clamped at its midpoint then the new frequency of oscillation is.
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Correct option: C
11.28 Hz11.28 \mathrm{~Hz}
Option A (−2i^+45j^−29k^-2 \hat{i}+45 \hat{j}-29 \hat{k}) is correct because the linear velocity is the cross product of the angular velocity and the position vector.

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