If $\frac{{dy}}{{dx}}\, = \,\frac{{{2^{x + y}} - {2^x}}}{{{2^y}}},\,y(0)\, = \,1$ then $y(1)$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\frac{{dy}}{{dx}}\, = \,\frac{{{2^{x + y}} - {2^x}}}{{{2^y}}},\,y(0)\, = \,1

then

y(1)

is equal to

View answer and explanation

Correct option: B

{\log _2}(1 + e)

Option B (

{\log _2}(1 + e)

) is correct because it is the solution to the differential equation with the given initial condition.

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