JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

\left( {\cos \theta + i\sin \theta } \right)\left( {\cos 2\theta + i\sin 2\theta } \right) \ldots \left( {\cos n\theta + i\sin n\theta } \right) = 1

then the value of

\theta

View answer and explanation

Correct option: C

\frac{{4m\pi }}{{n\left( {n + 1} \right)}}

The correct answer is C (

\frac{{4m\pi }}{{n\left( {n + 1} \right)}}

) because using De Moivre's theorem and equating to 1 leads to this solution for

\theta

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