JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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For solving

\frac{{dy}}{{dx}} = 4x + y + 1

, suitable substitution is

View answer and explanation

Correct option: D

y + 4x + 1 = v

The correct answer is D (

y + 4x + 1 = v

) because it follows the standard substitution method for solving differential equations of the form

\frac{{dy}}{{dx}} = f(ax + by + c)

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y=y(x)

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{x^2} + {y^2} = 1

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y=y(t)

\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}

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\lim \limits_{{x \rightarrow \infty}} y(t)