The order of decreasing reactivity towards ${S_E}\;$reaction for the given compound is: (i) ${{\rm{C}}_6}{{\rm{H}}_6}$ (ii) ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_3}$ (iii) ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{Cl}}$ (iv) ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{OH}}$

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NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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The order of decreasing reactivity towards

{S_E}\;

reaction for the given compound is:
(i)

{\mathrm{C}_6}{\mathrm{H}_6}

(ii)

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_3}

(iii)

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{Cl}

(iv)

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}

View answer and explanation

Correct option: C

(iv) > (ii) > (i) > (iii)

Option C (iv) > (ii) > (i) > (iii) is correct because electron donating groups increase reactivity towards electrophilic substitution, while electron withdrawing groups decrease it.

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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