If $0 < {\rm{\theta }} < {\rm{\pi }},$ then the minimum value of ${\sin ^5}\theta + {\rm{cose}}{{\rm{c}}^5}{\rm{\theta }}$ is

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

0 < \mathrm{\theta } < \mathrm{\pi },

then the minimum value of

{\sin ^5}\theta + \mathrm{cose}{\mathrm{c}^5}\mathrm{\theta }

View answer and explanation

Correct option: C

Option C (2) is correct because the minimum value is found using the fact that

x + \frac{1}{x} \ge 2

for all

x > 0

, applied to the given expression.

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