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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1
A2+B2→2AB.ΔHf=−200 kJ mol−1\mathrm{A}_{2}+\mathrm{B}_{2} \rightarrow 2 \mathrm{AB} . \Delta \mathrm{H}_{\mathrm{f}}=-200 \,\mathrm{kJ} \,\mathrm{mol}^{-1}
AB,A2\mathrm{A B, A_{2}} and B2\mathrm{B_{2}} are diatomic molecules. If the bond enthalpies of A2,B2\mathrm{A_{2}, B_{2}} and AB\mathrm{A B} are in the ratio 1:0.5:11: 0.5: 1, then the bond enthalpy of A2\mathrm{A_{2}} is ____ kJ mol−1\mathrm{kJ} \,\mathrm{mol^{-1}} (Nearest integer)
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Correct option: A
400
Option A (400) is correct because the bond enthalpy of A2 is calculated by using the given ratio of bond enthalpies and the enthalpy of formation.

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