Skip to main content
Back to SEMI CONDUCTOR DEVICES

JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

1 Medium
1 of 1
Remembering +4 | -1
The relation between α\alpha and β\beta parameters of current gains for a transistors is given by:
View answer and explanation
Correct option: B
α=β1+β\alpha = \frac{\beta }{{1 + \beta }}
Option B (α=β1+β\alpha = \frac{\beta }{{1 + \beta }}) is correct because it represents the correct relationship between the common-base current gain (α\alpha) and the common-emitter current gain (β\beta) in a transistor.

More Questions from SEMI CONDUCTOR DEVICES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.