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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If

\mathbf{f}(\mathbf{x})=\log \left(\frac{1+\mathrm{x}}{1-\mathrm{x}}\right), \mathbf{- 1}<\mathbf{x}<\mathbf{1}

, then

\mathbf{f}\left(\frac{3 \mathrm{x}+\mathrm{x}^3}{1+3 \mathrm{x}^2}\right)-\mathrm{f}\left(\frac{2 \mathrm{x}}{1+\mathrm{x}^2}\right)

is

\mathbf{M}

f(x)

then the value of

M

is

View answer and explanation

Correct option: A

1

Option A (1) is correct because simplifying the expression leads to M = 1.

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