$(p \wedge \sim q) \wedge(\sim p \wedge q)$ is

Both a tautology and a contradiction

Neither a tautology nor a contradiction

JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

1 Easy

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(p \wedge \sim q) \wedge(\sim p \wedge q)

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Correct option: B

A contradiction

Option B (A contradiction) is correct because the given expression simplifies to a contradiction using associative and commutative laws.

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p:A

q:A

\sqrt{3}

p

q

p \rightarrow q

{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

p

n

q:

n

p \Leftrightarrow q