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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫cos⁡x4−sin⁡2xdx=\int \cos x \sqrt{4-\sin ^2 x} d x=
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Correct option: B
12sin⁡x4−sin⁡2x+2sin⁡−1(12sin⁡x)+c\frac{1}{2} \sin x \sqrt{4-\sin ^2 x}+2 \sin ^{-1}\left(\frac{1}{2} \sin x\right)+c
Option B is correct because the integral can be solved using trigonometric substitution, resulting in 12sin⁡x4−sin⁡2x+2sin⁡−1(12sin⁡x)+c\frac{1}{2} \sin x \sqrt{4-\sin ^2 x}+2 \sin ^{-1}(\frac{1}{2} \sin x)+c.

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