JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

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Application +4 | -1

The solution of initial value problem

x y^{\prime}+y

=0, y(2)=-2

is given by

View answer and explanation

Correct option: A

x y+4=0

Option A (

x y+4=0

) is correct because it is the solution to the differential equation

x y^{\prime}+y=0

with the initial condition

y(2)=-2

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