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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫1(x2+a2)(x2+b2)dx=\int \frac{1}{\left(x^2+a^2\right)\left(x^2+b^2\right)} d x=
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Correct option: A
1(a2−b2)[1btan⁡−1(xb)−1atan⁡−1(xa)]+c\frac{1}{\left(a^2-b^2\right)}\left[\frac{1}{b} \tan ^{-1}\left(\frac{x}{b}\right)-\frac{1}{a} \tan ^{-1}\left(\frac{x}{a}\right)\right]+c
Option A is correct because the integral is solved using partial fraction decomposition, resulting in the given expression.

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