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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a Δ ABC\Delta \,ABC, if A=30∘,  b=2,  c=3+1A = 30^\circ ,\,\,b = 2,\,\,c = \sqrt 3 + 1, then C−B2=\frac{{C - B}}{2} =
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Correct option: B
30∘30^\circ
Option B (30∘30^\circ) is correct because applying the tangent half-angle formula and solving for C−B2\frac{{C - B}}{2} yields 30∘30^\circ.

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