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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A hollow sphere of mass 2 kg2 \mathrm{~kg} and radius 2 cm2 \mathrm{~cm} is rolling down a rough incline of inclination θ=30∘\theta=30^{\circ}. The acceleration of its centre down the incline is (g=10 m/s2)\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)
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Correct option: C
3 m/s23 \mathrm{~m} / \mathrm{s}^2
Option C (3 m/s23 \mathrm{~m} / \mathrm{s}^2) is correct because it is the acceleration calculated using the formula for a hollow sphere rolling down an incline.

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