JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1

Let

\int \,\,\frac{{{x^2}}}{{\sqrt {1 - x} }}\,\,dx = p\,\,\sqrt {\left( {1 - x} \right)} \,\,\left( {3{x^2} + 4x + 8} \right)

, then value of

p

View answer and explanation

Correct option: A

\frac{{ - \,2}}{{15}}

Option A (

\frac{{ - \,2}}{{15}}

) is correct because substituting

1-x = t^2

and integrating yields the correct value for p.

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