The enthalpy and entropy change for a chemical reaction are $ - \,2.5\,\, \times {10^{\rm{3}}}{\rm{cal}}\,\,{\rm{and}}\,\,7.4\,\,cal\,{K^{ - 1}}$ respectively.Predict that nature of reaction at 298 K is:

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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The enthalpy and entropy change for a chemical reaction are 

- \,2.5\,\, \times {10^\mathrm{3}}\mathrm{cal}\,\,\mathrm{and}\,\,7.4\,\,cal\,{K^{ - 1}}

  respectively.Predict that nature of reaction at 298 K is:

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Correct option: A

Spontaneous

Option A (Spontaneous) is correct because the Gibbs free energy change is negative, indicating a spontaneous reaction at 298 K.

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{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G