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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In a △ABC,a=4,b=3,∠A=60∘\triangle A B C, a=4, b=3, \angle A=60^{\circ}, then cc is the root of the equation
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Correct option: A
c2−3c−7=0c^2-3 c-7=0
Option A (c2−3c−7=0c^2-3c-7=0) is correct because by applying the Law of Cosines and substituting the given values, we can derive the quadratic equation c2−3c−7=0c^2-3c-7=0.

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