JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

For

x \in\left(0, \frac{3}{2}\right), \operatorname{let} f(x)=\sqrt{x}, g(x)=\tan x

and

h(x)=\frac{1-x^{2}}{1+x^{2}}

. If

\phi(x)=((h \circ f) \circ g)(x)

, then

\phi\left(\frac{\pi}{3}\right)

is equal to :

View answer and explanation

Correct option: B

\tan \frac{11 \pi}{12}

The correct answer is B (tan(11π/12)) because it involves evaluating composite functions and using trigonometric identities.

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f\left( x \right) = x - \left[ x \right]

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f(x)=x^4

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S=\left\{x: f(x)=f^{-1}(x)\right\}