JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

The root of the equation

2\left( {1 + i} \right){x^2} - 4\left( {2 - i} \right)x - 5 - 3i = 0,

where

i = \sqrt { - 1} ,

which has greater modulus, is

View answer and explanation

Correct option: A

\frac{{3 - 5i}}{2}

Option A (

\frac{{3 - 5i}}{2}

) is correct because it is one of the roots of the quadratic equation and has a greater modulus than the other root.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

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2x = - 1 + \sqrt 3 i

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