Back to OSCILLATIONS

JEE PHYSICS MCQ: OSCILLATIONS

1 Medium

1 of 1

Application +4 | -1

A ring of radius

20 \mathrm{~cm}

is hinged from a point on its periphery. The time period of its oscillations will be

\left(g=9.8 \mathrm{~m} / \mathrm{s}^2\right)

View answer and explanation

Correct option: C

\frac{2 \sqrt{2} \pi}{7} \mathrm{~s}

Option C (

\frac{2 \sqrt{2} \pi}{7} \mathrm{~s}

) is correct because it is the calculated time period of oscillation for a ring hinged at a point on its periphery using the formula

T=2 \pi \sqrt{\frac{2R}{g}}

.

More Questions from OSCILLATIONS

Practice All Chapter MCQs →

Assertion: A particle executing simple harmonic motion comes to rest at the extreme positions.

Reason: The resultant force on the particle is zero at these positions. A particle is subjected simultaneously to two SHM’s one along the

x

-axis and the other along the

y

-axis. The two vibrations are in phase and have unequal amplitudes. The particle will execute A particle is executing SHM with amplitude

a

. When the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be The displacement, velocity and acceleration in a simple harmonic motion are related as the Assertion: Angular velocity of earth around sun is lesser than the angular velocity of moon about earth.
Reason: Time taken by moon revolve around earth is less than time taken by earth to revolve around sun. A particle is executing

SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)