JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

Let

f(\theta)=\tan \left(\frac{\pi}{3}+\theta\right) \tan \left(\frac{\pi}{3}-\theta\right)

-\frac{\pi}{3}<\theta<\frac{\pi}{3}

, then

f\left(\frac{\pi}{12}\right)

is equal to:

View answer and explanation

Correct option: A

2+\sqrt{3}

The correct answer is A (

2+\sqrt{3}

) because by using trigonometric identities and substituting the value of

\theta

, we can simplify the expression to obtain the result.

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