Skip to main content
Back to CHEMICAL KINETICS

NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

1 Medium
1 of 1
Analyzing +4 | -1
Consider the reaction,

Cl2(aq)+H2S(aq)→S(s)+2H+(aq)+2Cl−(aq)C{l_2}\left( {aq} \right) + {H_2}S\left( {aq} \right) \to S\left( s \right) + 2{H^ + }\left( {aq} \right) + 2C{l^ - }\left( {aq} \right) the rate equation for this reaction is , rate=k[Cl2][H2S]rate = k\left[ {C{l_2}} \right]\left[ {{H_2}S} \right]

Which of these mechanisms is/are consistent with this rate equation?

A.    Cl2+H2S(aq)→H+Cl−+Cl++HS−(slow)          Cl++HS−→H+Cl−+S(fast)B.    H2S↔H++HS−(fast  equilibrium)        Cl2+HS−→2Cl−+H+S(slow)\begin{array}{l} A.\;\;C{l_2} + {H_2}S\left( {aq} \right) \to {H^ + }C{l^ - } + C{l^ + } + H{S^ - }\left( {slow} \right)\\ \;\;\;\;\;C{l^ + } + H{S^ - } \to {H^ + }C{l^ - } + S\left( {fast} \right)\\ B.\;\;{H_2}S \leftrightarrow {H^ + } + H{S^ - }\left( {fast\;equilibrium} \right)\\ \;\;\;\;C{l_2} + H{S^ - } \to 2C{l^ - } + {H^ + }S\left( {slow} \right) \end{array}
View answer and explanation
Correct option: D
(A)Only
Option D (All of the above) is correct because all the statements about the rate constants and equilibrium constant are derived correctly from the given net rate equation.

More Questions from CHEMICAL KINETICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.