If $ f(x)=\frac{x}{x-1} $, then $ \frac{f(a)}{f(a+1)}= $

$ f\left(\frac{-a}{a-1}\right) $

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f(x)=\frac{x}{x-1}

, then

\frac{f(a)}{f(a+1)}=

View answer and explanation

Correct option: C

f\left(a^{2}\right)

Option C (

f(a^{2})

) is correct because when you simplify

\frac{{f(a)}}{{f(a+1)}}

, it results in

\frac{{a^2}}{{a^2-1}}

, which is equivalent to

f(a^2)

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