Oxidation number of $S$ in ${{\rm{S}}_2}{\rm{C}}{{\rm{l}}_2}$ is :

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Medium

1 of 1

Application +4 | -1

Oxidation number of

S

{\mathrm{S}_2}\mathrm{C}{\mathrm{l}_2}

is :

View answer and explanation

Correct option: A

+ 1

Option A (+1) is correct because the oxidation number of Cl is -1, and the overall molecule is neutral, leading to +1 for S.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }