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JEE PHYSICS MCQ: GRAVITATION

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Application +4 | -1
The K.E of a satellite is 104J{10^4}J. It s P.E is
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Correct option: C
−2×104 J- 2 \times {10^4}\,J
Option C (−2×104 J- 2 \times {10^4}\,J) is correct because the potential energy of a satellite is -2 times its kinetic energy.

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