JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\theta=\frac{\pi}{2^n+1}

then the value of

\cos \theta \cos 2 \theta \cos 2^2 \theta \ldots \ldots \cos 2^{n-1} \theta

is equal to -

View answer and explanation

Correct option: B

1 / 2^n

Option B (

1 / 2^n

) is correct because the expression simplifies to

\frac{{\sin 2^n \theta}}{{2^n \sin \theta}}

, which then simplifies to

1 / 2^n

using the given condition.

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\triangle A B C

C

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