NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Hard

1 of 1

Application +4 | -1

The oxidation state of the most electronegative element in the products of the reaction between

\mathrm{BaO}_2

and

\mathrm{H}_2 \mathrm{SO}_4

are

View answer and explanation

Correct option: B

-1

and

-2

Option B (-1 and -2) is correct because in the reaction of BaO2 with H2SO4, the products are BaSO4 and H2O2. The oxidation state of O in BaSO4 is -2, and in H2O2, it is -1. Oxygen is the most electronegative element in both products.

More Questions from REDOX REACTIONS

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The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated

{I_2}

is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction,

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

coefficient of reactants in balanced states are

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }

Which one of the following reaction is possible at anode? The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called