JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Application +4 | -1

Moment of inertia of a uniform circular disc about a diameter is

\frac{I}{2}

. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be

View answer and explanation

Correct option: C

3 I

Option C (3 I) is correct because the moment of inertia about a diameter is

\frac{1}{4}MR^2

, and using the parallel axis theorem, the moment of inertia about an axis perpendicular to the plane and passing through a point on its rim is

\frac{3}{2}MR^2

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)