In the contact process of ${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4},{\rm{\;S}}{{\rm{O}}_3}$ dissolves in sulphuric acid to give:

JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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In the contact process of

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4},\mathrm{\;S}{\mathrm{O}_3}

dissolves in sulphuric acid to give:

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Correct option: C

Pyrosulphuric acid

Option C (Pyrosulphuric acid) is correct because

SO_3

dissolves in sulphuric acid to form pyrosulphuric acid (

H_2S_2O_7

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4