JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A particle of mass m is circulating on a circle of radius r having angular momentum L, then the centripetal force will be

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Correct option: C

{L^2}/m{r^3}

Option C (

{L^2}/m{r^3}

) is correct because the centripetal force can be expressed in terms of angular momentum as

{L^2}/m{r^3}

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)