JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

In a

\triangle A B C, \angle C=60^{\circ}

, then

\frac{1}{a+c}+\frac{1}{b+c}

is equal to

View answer and explanation

Correct option: C

\frac{3}{a+b+c}

Option C (

\frac{3}{a+b+c}

) is correct. By using the cosine rule with

\angle C = 60^{\circ}

and manipulating the resulting equation, the given expression can be simplified to

\frac{3}{a+b+c}

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