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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
If 1,  ω,  ω21,\;\omega ,\;{\omega ^2} are the cube roots of unity, then (1−ω+ω2)(1−ω2+ω4)(1−ω4+ω8)(1−ω8+ω16)\left( {1 - \omega + {\omega ^2}} \right)\left( {1 - {\omega ^2} + {\omega ^4}} \right)\left( {1 - {\omega ^4} + {\omega ^8}} \right)\left( {1 - {\omega ^8} + {\omega ^{16}}} \right) upto 2n2n factors is
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Correct option: B
22n{2^{2n}}
Option B (22n{2^{2n}}) is correct because each pair of factors simplifies to 4, and there are n such pairs.

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