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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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In a composite rod, when two rods of different lengths and of the same area of cross-section are joined end to end, then if KK is the effective coefficient of thermal conductivity, l1+l2K\frac{l_1+l_2}{K} is equal to:
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Correct option: C
l1K1+l2K2\frac{l_1}{K_1}+\frac{l_2}{K_2}
Option C (l1K1+l2K2\frac{l_1}{K_1}+\frac{l_2}{K_2}) is correct because it represents the sum of thermal resistances of the two rods in series.

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