The addition of dilute $NaOH$ to $C{r^{3 + }}$ salt solution will give

a solution of ${[Cr{(OH)_4}]^ - }$

Precipitate of ${[Cr{(OH)_6}]^{3 - }}$

JEE CHEMISTRY MCQ: S-BLOCK ELEMENTS

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Understanding +4 | -1

The addition of dilute

NaOH

C{r^{3 + }}

salt solution will give

View answer and explanation

Correct option: B

Precipitate of

C{r_2}{O_3}{({H_2}O)_n}

Option B (Precipitate of

C{r_2}{O_3}{({H_2}O)_n}

) is correct because the addition of dilute NaOH to a Cr3+ salt solution results in the precipitation of hydrated chromium(III) oxide.

Practice All Chapter MCQs →

(A)

(A)

\mathrm{K}_2 \mathrm{CrO}_4

\mathrm{AgNO}_3

\mathrm{H}_2 \mathrm{~S}

\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3

\mathrm{NH}_4 \mathrm{OH}

0.297 \mathrm{~g}

(A)

0.197 \mathrm{~g}

(B)

(A)

\mathrm{KCl}

\mathrm{NaCl}

{LiCl}

{Li}

{Cl}