JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1

f2(x) = {\tan ^{ - 1}}(\sec x + \tan x), - \frac{\pi }{2} < x < \frac{\pi }{2},\,\,{\text{and}}\,\,f(0) = 0,\,\,{\text{then}}\,\,f(1)

is equal to:

View answer and explanation

Correct option: A

\frac{\pi+1}{4}

Option A (

\frac{{\pi+1}}{{4}}

) is correct because it is the value of f(1) obtained after integrating f'(x) and applying the initial condition f(0) = 0.

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