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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
Let z1z_1 and z2z_2 be given by z1=(2+i52−i5)10 and z2=(2−i52+i5)10z_1=\left(\frac{2+i \sqrt{5}}{2-i \sqrt{5}}\right)^{10} \text { and } z_2=\left(\frac{2-i \sqrt{5}}{2+i \sqrt{5}}\right)^{10}
Then ∣z1+z2∣\left|z_1+z_2\right| is equal to
View answer and explanation
Correct option: A
2cos⁡(20cos⁡−123)2 \cos \left(20 \cos ^{-1} \frac{2}{3}\right)
Option C (2cos⁡(10cos⁡−123)2 \cos \left(10 \cos ^{-1} \frac{2}{3}\right)) is correct because by converting to polar form and using De Moivre's theorem, the expression simplifies to this result.

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