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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
Let f(θ)=tan⁡3θ1+tan⁡2θ−cot⁡3θ1+cot⁡2θ,0<θ<π4f(\theta)=\frac{\tan ^3 \theta}{1+\tan ^2 \theta}-\frac{\cot ^3 \theta}{1+\cot ^2 \theta}, 0<\theta<\frac{\pi}{4}. Then f(θ)f(\theta) is equal to
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Correct option: C
−2cot⁡(2θ)-2 \cot (2 \theta)
Option C (−2cot⁡(2θ)-2 \cot (2 \theta)) is correct because the expression simplifies to −2cot⁡(2θ)-2 \cot (2 \theta) using trigonometric identities.

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