JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Understanding +4 | -1

\left\{ {x \in R:\frac{{2x - 1}}{{{x^3} + 4{x^2} + 3x}} \in R} \right\}

equals

View answer and explanation

Correct option: C

R - \left\{ {0,\; - 1,\; - 3} \right\}

Option C (

R - \left\{ {0,\; - 1,\; - 3} \right\}

) is correct because the expression is real for all real numbers except where the denominator is zero, which occurs at x = 0, -1, and -3.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}