JEE MATHEMATICS MCQ: RELATIONS

1 Easy

1 of 1

Application +4 | -1

f(x)=4 x-x^2, x \in R

, then

f(b+1)-f(b-1)

is equal to

{m}(2-{b})

. The value of '

{m}

' is

View answer and explanation

Correct option: A

Option A (4) is correct because expanding f(b+1) - f(b-1) and comparing it to m(2-b) gives m = 4.

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