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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A body of weight

30 \mathrm{~N}

hangs from one end of a long, vertical spring whose other end is attached to a rigid support. The spring extends by

5 \mathrm{~cm}

when a force of

10 \mathrm{~N}

is applied to it. The time period of the vertical oscillations of the body is

View answer and explanation

Correct option: B

(\pi / 5) \sqrt{(3 / 2)} \,\mathrm{sec}

Option B (

\frac{\pi}{5} \sqrt{\frac{3}{2}} \,\mathrm{sec}

) is correct because the time period of vertical oscillations can be calculated using the spring constant and the mass of the body.

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