What volume of 3 molar ${\rm{HN}}{{\rm{O}}_3}$ is needed to oxidise 8 g of ${\rm{F}}{{\rm{e}}^{2 + }}$ to ${\rm{F}}{{\rm{e}}^{3 + }}$ ${\rm{HN}}{{\rm{O}}_3}$, gets converted to NO :

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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What volume of 3 molar

\mathrm{HN}{\mathrm{O}_3}

is needed to oxidise 8 g of

\mathrm{F}{\mathrm{e}^{2 + }}

\mathrm{F}{\mathrm{e}^{3 + }}

\mathrm{HN}{\mathrm{O}_3}

, gets converted to NO :

View answer and explanation

Correct option: B

16 m L

Option B (16 m L) is correct because it is calculated using stoichiometry based on the balanced redox reaction and the molarity of the HNO3 solution.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }