JEE MATHEMATICS MCQ: CIRCLES

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Analyzing +4 | -1

Let

S \equiv 0

and

S^{\prime} \equiv 0

be two circles belonging to the family of circles

x^2+y^2+\lambda x-4 y+3=0:(\lambda

\in \mathrm{R})

such that

S \equiv 0

bisects the circumference of circle

S^{\prime} \equiv 0

and has radius equal to twice of radius of

{S}^{\prime} \equiv 0

. Then distance between their centres is

View answer and explanation

Correct option: B

Option B (1) is correct because the distance between the centers of the two circles is calculated to be 1 unit based on the given conditions.

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9 \pi